Hi,
The attached macro ( trial2.cxx ) demonstrates the bug(s).
Proper "compiler" output :
--------------------------
donald duck
xx -> 1 *p_x -> 0
xyz->x(1)[0] = 10 -> 10
yy -> 2 *p_y -> 0
*xyz->y(2) -> 2
zz -> 3 *p_z -> 0
xyz->z(3)[0] = 30 -> 30
*p_y -> 2 -> 6
*xyz->y() = 5 -> 5
*p_y -> 5 -> 6
4 6 30
miki mouse
--------------------------
Wrong CINT output :
--------------------------
donald duck
Error: G__getvariable: expression [0] FILE:/home/holeczek/src/test/./t11.cxx LINE:27
Error: improper lvalue FILE:/home/holeczek/src/test/./t11.cxx LINE:27
(int)10
*** Interpreter error recovered ***
--------------------------
Even if I comment lines 27,28,29 I still get CINT errors :
--------------------------
donald duck
Error: Incorrect assignment to p_y FILE:/home/holeczek/src/test/./t11.cxx LINE:11
Error: improper lvalue FILE:/home/holeczek/src/test/./t11.cxx LINE:32
*p_y -> 0(int)5
*** Interpreter error recovered ***
--------------------------
Seems that functions that return pointers are improperly parsed.
Jacek.
#include <stream.h>
class XYZ {
public:
int p_x[10];
int p_y[20];
int p_z[30];
int *x() {return p_x;}
// int *y() {return p_y;}
int *y() {cout << "*p_y -> " << *p_y ;*p_y=6;cout << " -> " << *p_y << endl;return p_y;}
int *z() {return p_z;}
XYZ() {return;}
~XYZ() {return;}
int *x(int xx) {cout << "xx -> " << xx << " *p_x -> " << *p_x << endl;p_x[0]=xx;return p_x;}
int *y(int yy) {cout << "yy -> " << yy << " *p_y -> " << *p_y << endl;p_y[0]=yy;return p_y;}
int *z(int zz) {cout << "zz -> " << zz << " *p_z -> " << *p_z << endl;p_z[0]=zz;return p_z;}
};
main()
{
XYZ *xyz = new XYZ;
cout << "donald duck" << endl;
xyz->x(1)[0] = 10; cout << "xyz->x(1)[0] = 10 -> " << *xyz->p_x << endl;
xyz->y(2); cout << "*xyz->y(2) -> " << *xyz->p_y << endl;
xyz->z(3)[0] = 30; cout << "xyz->z(3)[0] = 30 -> " << *xyz->p_z << endl;
xyz->x()[0] = 4;
xyz->y()[0] = 5; cout << "*xyz->y() = 5 -> " << *xyz->p_y << endl;
cout << *xyz->x() << " " << *xyz->y() << " " << *xyz->z() << endl;
cout << "miki mouse" << endl;
}
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