Hi Viktor, Well, if I do for example TList* List1 = new TList(); TList* List2 = new TList(); TObject *Object = new TObject(); List1->AddLast(Object); List2->AddLast(Object); List1->Write(1); List2->Write(1); would not Object be written twice? What happens if I read these two lists back? Will I get one or two different Objects? Best, Anton -----Original Message----- From: perev@rcf.rhic.bnl.gov [mailto:perev@rcf.rhic.bnl.gov]On Behalf Of Victor Perevoztchikov Sent: Monday, January 31, 2000 3:26 PM To: Anton Fokin Cc: roottalk@pcroot.cern.ch Subject: Re: How to stream this? Hi Anton, > I will get two copies of Obj. I could not find a solution except writing a ROOT I/O does not write the same object twice. Probably you did something in non standard way. Show please your example how do you write. Victor Anton Fokin wrote: > > Hi, > > I would like to stream a structure like this > > Obj1 *--> Obj <--* Obj2 > > where Obj1 and Obj2 have pointers to the same object Obj. If I stream it in > a "normal" way, Obj1::Streamer() will invoke Streamer() of Obj and > Obj2::Streamer() will do the same. The same happens if I read it back, i.e. > I will get two copies of Obj. I could not find a solution except writing a > numerical id instead of pointers and connecting object after reading. Any > suggestions? > > Best, > Anton -- Victor M. Perevoztchikov perev@bnl.gov perev@vxcern.cern.ch Brookhaven National Laboratory MS 510A PO Box 5000 Upton NY 11973-5000 tel office : 631-344-7894; fax 631-344-4206; home 631-345-2690
This archive was generated by hypermail 2b29 : Tue Jan 02 2001 - 11:50:18 MET