Re: a simple arithmetic(?)

From: Rene Brun (Rene.Brun@cern.ch)
Date: Tue Feb 22 2000 - 09:44:36 MET 

This is the expected result.
Replace
a = (Double_t)((b-c)/b)
by
a = (Double_t)(b-c)/b

Rene Brun

allister@physics.msuiit.edu.ph wrote:
> 
> Hi Rooters,
> 
> I tried this simple (?) operation:
> 
> root [12] Double_t a
> root [13] Int_t b
> root [14] Int_t c
> root [15] b = 354
> (int)354
> root [16] c = 245
> (int)245
> root [17] a = (b-c)/b
> (Int_t)0
> root [18] a = (Double_t)((b-c)/b)
> (Double_t)0.00000000000000000e+00
> 
> Why is "a" still zero?  Am I missing something here?
> 
> Thanks in advance,
> 
> Allister Levi C. Sanchez
> IITHEP, Department of Physics
> MSU - Iligan Institute of Technology
> 9200 Iligan City
> Philippines

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