Re: [ROOT] How to fill tree with character string?

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Hi Valeriy,

A precision about my mail yesterday. Your first test1.C will work correctly
with:
   leafStr = "EMPNO/I:ENAME[40]/C:JOB[40]/C:MGR/I:SAL/I:DEPTNO/I";
test2.C will not work.

Rene Brun

Valeriy Onuchin wrote:
> 
>   Hi,
> is it  possible to fill tree with " a character string terminated
> by the 0 character" ?
>  I tried the followng macros , but both gave wrong output.
> What's I'm doing wrong?
>  Thanks. Regards.    Valeriy
> 
> ///////////////////////////  test1.C ///////////////////////////////////////
> {
>    typedef struct {
>       Int_t EMPNO;
>       char ENAME[40];
>       char JOB[40];
>       Int_t MGR;
>       Int_t SAL;
>       Int_t DEPTNO;
>    } EMP;
> 
>    static EMP emp;
> 
>    TString leafStr;
>    leafStr = "EMPNO/I:ENAME/C:JOB/C:MGR/I:SAL/I:DEPTNO/I";
> 
>    //create tree
>    TTree *tree = new TTree("T","EMP table");
>    tree->Branch("emp",&emp,leafStr.Data());
> 
>    // filling
>    emp.EMPNO = 7369;
>    strcpy(emp.ENAME,"SMITH");
>    strcpy(emp.JOB,"CLERK");
>    emp.MGR = 7902;
>    emp.SAL = 800;
>    emp.DEPTNO = 20;
>    tree->Fill();
> 
>    emp.EMPNO = 7499;
>    strcpy(emp.ENAME,"ALLEN");
>    strcpy(emp.JOB,"SALESMAN");
>    emp.MGR = 7698;
>    emp.SAL = 1600;
>    emp.DEPTNO = 30;
>    tree->Fill();
> 
>    tree->Show(0);
>    tree->Show(1);
> }
> 
> ///////////////////////////  test2.C ///////////////////////////////////////
> {
>    typedef struct {
>       Int_t EMPNO;
>       char* ENAME;
>       char* JOB;
>       Int_t MGR;
>       Int_t SAL;
>       Int_t DEPTNO;
>    } EMP;
> 
>    static EMP emp;
> 
>    TString leafStr;
>    leafStr = "EMPNO/I:ENAME/C:JOB/C:MGR/I:SAL/I:DEPTNO/I";
> 
>    //create tree
>    TTree *tree = new TTree("T","EMP table");
>    tree->Branch("emp",&emp,leafStr.Data());
> 
>    // filling
>    emp.EMPNO = 7369;
>    emp.ENAME="SMITH";
>    emp.JOB="CLERK";
>    emp.MGR = 7902;
>    emp.SAL = 800;
>    emp.DEPTNO = 20;
>    tree->Fill();
> 
>    emp.EMPNO = 7499;
>    emp.ENAME="ALLEN";
>    emp.JOB="SALESMAN";
>    emp.MGR = 7698;
>    emp.SAL = 1600;
>    emp.DEPTNO = 30;
>    tree->Fill();
> 
>    tree->Show(0);
>    tree->Show(1);
> }

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