Example char filename[256]; cin >> filename; FILE *fp = fopen(filename,"r"); Rene Brun On Sat, 27 Apr 2002, HALASYA SHIVA wrote: > Dear Rene, > Sorry, I was out of town, so couldn't reply immediately. I am hereby > sending the datafile and the script file as attachments. > " I have one more question, this is a trivial question may be... > You know we can access files from command line in C++ using argc, argv[] > declarations in the main, likewise, even in C++ or root, how can I read the > file name as a string while running the program. means... > fp = fopen("data.dat","r"); > instead of this, I would like to declare > char *ar[]; > gets(ar[1]); > fp = fopen(ar[1],"r"); and then access my file. > Can I do this or not? > When I am doing this, its not recognizing the ar[1] value as a file name, > where am I going wrong? Please reply. Thanx > Yours, > Shiva. > > On Wed, 17 Apr 2002, Rene Brun wrote: > > >Please, send me a small data file + a script showing the problem. > > > >Rene Brun > > > >On Wed, 17 Apr 2002, Siva Subramania wrote: > > > > > Dear Rene, > > > I dont understand why this happens? First of all, thanx a lot for > > > helping me in fitting gaussian to ntuples. Now everything is going fine, > > > but whenever I have a dataset with numbers greater than one and the > > > range of the data numbers(of 400 data points say) for example lies > >between > > > 2.3 to 2.6, and I plot an ntuple and fit, I am getting a mean value of > > > 0.5 something irrelevant to the data that I am feeding in. But when I > > > make the numbers to become less than 1,say 0.23 to .26 then I am getting > > > relevant results ie the mean is now between the range (0.244). Is > > > that a bug of any of the version b'coz I am using one of the previous > > > versions of root.Probably 3.00. How can I get around it? Please reply. > > > Thanx, > > > yours, > > > Shiva. > > > > > > > > _________________________________________________________________ > Send and receive Hotmail on your mobile device: http://mobile.msn.com >
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