Hi Francois-Xavier,
If you did everything right (and I think you did) then you have got
already all that you want: these names mean that you have several
versions of your tree, but you can use the whole tree anyway.
Just use the name "T" (not "T;123"), and you will get all the entries.
for example
tree->GetEntries();
will print all entries, and even
tree->Draw("bla-bla-bla")
draw all variables.
Best regards,
Stanislav.
> On Tue, 3 Sep 2002 16:19:32 +0200
> GENTIT Francois-Xavier DAPNIA <GENTIT@dapnia.cea.fr> wrote
> concerning "[ROOT] Adding one more element to a tree":
> > Dear Rooters,
> > What is the trick to add more elements to an already existing tree?
> > To try to find it myself, I have taken the example "staff.C" in the
> > tutorials. I have split cernstaff.dat into cernstaff1.dat and
> > cernsatff2.dat, cernstaff1.dat being without the last element of
> > cernstaff.dat, and cernstaff2.dat containing only this last element.
> > I have then run "staff.C", obtaining correctly a tree of 3353 elements.
> > Then I have run a script "staff2.C", which is identical with staff.C,
> > except for these 3 lines:
> >
> > FILE *fp = fopen("cernstaff2.dat","r");
> >
> > TFile *f = new TFile("staff.root","UPDATE"); [instead of "RECREATE"]
> > TTree *tree = (TTree *)f->Get("T"); [instead of new TTree]
> >
> > But instead of obtaining a tree with 3354 elements, I obtain 2 trees, the
> > first T;1 one with 3353 elements, and a second one, T;2 with 1 element!!
> >
> > Thanks for your help
> >
> > François-Xavier Gentit
> > DAPNIA/SPP CEA Saclay
> > http://gentit.home.cern.ch/gentit/
> >
> >
>
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