As already reported yesterday, you cannot make the assumption that the
size of a structure is equal to the sum of the sizes of its components
when the components have different lengths.
Rene Brun
On
Wed, 2 Apr 2003, Huang Xingtao wrote:
> For example:
> void main() {
> struct A{
> unsigned int a;
> unsigned int b;
> short int c;
> };
> cout<<"Size of A:"<<sizeof(A)<<endl;
> }
>
> ----- Original Message -----
> From: "Rene Brun" <Rene.Brun@cern.ch>
> To: "Huang Xingtao" <huangxt@hepg.sdu.edu.cn>
> Cc: <roottalk@pcroot.cern.ch>
> Sent: Tuesday, April 01, 2003 4:47 PM
> Subject: Re: [ROOT] About the size of struct in ROOT
>
>
> > Hi,
> >
> > This may happen because of type alignment.
> > Please give an example.
> >
> > Rene Brun
> >
> > Huang Xingtao wrote:
> > >
> > > Part 1.1 Type: Plain Text (text/plain)
> > > Encoding: base64
> > I use the Root (3.01/06) package. I meet the following problem. The size of the
> > struct gived by ROOT is greater than the sum of size of all the type in the
> > struct. I don't know how to calculat it in the ROOT.
>
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