Hi Ray,
Thanks for reporting this problem. We are working on a solution.
Cheers,
Philippe
-----Original Message-----
From: owner-roottalk@pcroot.cern.ch
[mailto:owner-roottalk@pcroot.cern.ch]On Behalf Of Ray Fliller III
Sent: Friday, April 18, 2003 2:57 PM
To: ROOT mailing list
Subject: [ROOT] operator in a namespace question
Hello Rooters.
I am using ROOT cvs from Monday 4/11 on LINUX. My question is this,
I have a the following class:
namespace FOO{
class bug{
private:
int i;
public:
bug(int j);
int get();
void set(int j);
friend bug operator+(const bug& rhs, int c);
};
};
Using the following LinkDef.
#ifdef __CINT__
#pragma link off all globals;
#pragma link off all classes;
#pragma link off all functions;
#pragma link C++ namespace FOO;
#pragma link C++ nestedclasses;
#pragma link C++ class FOO::bug-!;
#pragma link C++ function FOO::operator+(const bug&, int);
#endif
It compiles fine, but when I go to use it, I get the following problem:
root [0] FOO::bug c(10)
root [1] c.get()
(int)10
root [2] c+10
Error: operator+ not defined for FOO::bug FILE:(tmpfile) LINE:1
*** Interpreter error recovered ***
root [3] using namespace FOO
root [4] c+10
(class FOO::bug)146564000
root [5]
Attached are the files (along with the .cxx). I know that not using a
namespace would be easier, but in this case, I am constrained to using
one. Any help will be appreciated.
This is of course the usual stripped down version of a complicated
problem! :-)
Thanks.
--
RAINMAN
"How much does a piece of gum cost Ray?"
"About $100."
"How much does a new car cost Ray?"
"`Bout $100."
"There goes working for NASA!"
==================================================================
Ray Fliller: rfliller@bnl.gov Office Phone: (631)-344-6124
C-A Accelerator Physics Dept. Fax: (631)-344-5954
Building 911B
Brookhaven National Lab
Upton, NY 11973 Office: Room 211
http://www.agsrhichome.bnl.gov/People/rfliller/
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