I wonder if there is an easy way to project a TF2 to TF1, by fixing either x or y? I searched the ROOTtalk site and went through the document, but could not find it. Basically, I would like to have something like, for example: TF2 *f2 = new TF2("f2", "x*y/([0]**2+x**2+y**2)",-10,10,-10,10, 1); TF1 *f1 = f2->ProjectionX("_px", -1); // i.e. y=-1.0 Is it easy to implement something like that? Yiqun Wang
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