Hello,
probably this is a quite stupid question, but I did not find the answer by myself (well, I am not an expert in C++ programming).
The following code illustrates my problem
typedef struct {
char name[100];
int value;
}HEADER_PAIRS1;
typedef struct {
HEADER_PAIRS1 hdr[6];
int val[500];
} dataBlock_t;
void initTree()
{
dataBlock_t dataBl;
TFile *dataFile;
TTree *dataTreeSpecHdr;
TTree *dataTreeSpctr;
const Text_t *title = "Ca38_data";
const Text_t *fname = "tree.root";
Option_t *option = "RECREATE";
Int_t comp = 1;
dataFile = new TFile(fname,option,title,comp);
if(dataFile->IsOpen())
cout << "\n ROOT file: " << fname << " opend" << endl;
else
{
cerr << "\n Couldn't open ROOT file: " << fname << endl;
exit (-2);
}
dataTreeSpctr = new TTree("TreeSpctr", "TAMU Ca38, Sep, 2005, Lifetime, Spectra");
// ???? dataTreeSpctr->Branch("spctr",&dataBl.val,"Data[500]/I");
}
I would like to store in the tree object all information that is defined as a dataBlock_t structure (variable dataBl) as a Branch? How it would be possible?
Thanks for helping me.
Victor.
February 17, 2006 Received on Fri Feb 17 2006 - 20:37:55 MET
This archive was generated by hypermail 2.2.0 : Mon Jan 01 2007 - 16:31:57 MET