Re: Filling area under a curve

On Thu, Jun 08, 2006 at 12:04:38PM +0200, Olivier Couet wrote:

Hi!

> The low let part is left empty. The upper part of the contour is drawn
> (to draw a filled contour you need two contours at least). A simple way to
> obtain what you need is to "invert" your function. Instead of returning
> "z" return (xmax*xmax+ymax*ymax-z) and instead of drawing the level "excl"
> draw the level (xmax*xmax+ymax*ymax-excl)

Sometimes it can be so simple, that one doesn't see it anymore. Thanks very much!

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