Hi,
>> And the fit par[n] location in this expression.
>> Like gauss function form:
>> f(x)= par[1]*exp(1/par[3] *(x-par[2])^2) where the par[n] is the
>> fit
>> parameter
>>
>>
>> Best regard,
>> Fengchu
>>
>>
>>
>>
For a "gaus" function you have
gaus = par[0] * exp( - ( (x - par[1])^2 ) / ( 2 * par[2]^2 ) )
For a "landau" you have
landau = par[0] * Landau( (x - par[1] )/ par[2] )
where Landau(z) is defined as
http://en.wikipedia.org/wiki/Landau_distribution
Best Regards
Lorenzo Received on Fri Oct 16 2009 - 08:24:17 CEST
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