Now fixed.
On 5/25/11 1:43 AM, "wlavrijsen_at_lbl.gov" <wlavrijsen_at_lbl.gov> wrote:
>Noel,
>
>>>>> import ROOT
>>>>> g = ROOT.TGraph(3)
>>>>> g.GetN()
>> 3
>>>>> g = ROOT.TGraph2D(3)
>>>>> g.GetN()
>> 0
>>>>>
>>
>> ???
>
>there's an issue with construction/destruction ordering given that neither
>TGraph(2D) has a name, so after the construction the same object will be
>deleted due to it's reference going away.
>
>That said, I see the same in CINT:
>
>root [0] g = new TGraph(3);
>root [1] g->GetN()
>(const Int_t)3
>root [2] g2 = new TGraph2D(3);
>root [3] g2->GetN()
>(const Int_t)0
>root [4]
>
>so there must be something more to it ...
>
>Best regards,
> Wim
>--
>WLavrijsen_at_lbl.gov -- +1 (510) 486 6411 -- www.lavrijsen.net
>
Received on Fri Jun 10 2011 - 11:08:04 CEST
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