Time of TNode->Clone()

From: Alexander Zvyagin (zvyagin@mx.ihep.su)
Date: Thu Feb 19 1998 - 10:52:23 MET 

                                           IHEP, Protvino, Russia, 18-FEB-1998

    Dear all!

I have next macro:

// File b.C
void b(UInt_t N)
{
  if( N==0 ) N=1;

  gROOT->Reset();
  g1 = new TGeometry ("Tempory","Tempory geometry");

  new TBRIK("MAIN","This is main frame","void",10,10,10);
  main_node = new TNode("MAINnode","This is main node","MAIN");
  main_node->BuildListOfNodes();
  main_node->cd();

  new TBRIK("A","A","void",1,1,1);
  Anode = new TNode("Anode","Anode","A");

  TStopwatch timer;
  timer.Start();

  for( int i=0; i<N; i++ )
  {
    TNode *node = (TNode*) Anode->Clone();
    if( NULL==node )
    {
      printf("Can not create node.\n");
      exit(1);
    }
    main_node->GetListOfNodes()->Add(node);
  }

  timer.Stop();
  printf("N=%d    rate = %g seconds per node\n",N,timer.CpuTime()/N);

  return;
}



ROOT session:

  *******************************************
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  *   Version   1.03/09  16 December 1997   *
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CINT/ROOT C/C++ Interpreter version 5.13.36, Nov 30 1997
Type ? for help. Commands must be C++ statements.
Enclose multiple statements between { }.
root [0] .x b.C(7);
N=7    rate = 0.0128571 seconds per node
NULL
root [1] .x b.C(8);
N=8    rate = 0.025 seconds per node
NULL
root [2] .x b.C(9); 
N=9    rate = 0.0555556 seconds per node
NULL
root [3] .x b.C(10);
N=10    rate = 0.148 seconds per node
NULL
root [4] .x b.C(11);
N=11    rate = 0.541818 seconds per node
NULL
root [5] .x b.C(12);
N=12    rate = 2.43833 seconds per node
NULL
root [6] .x b.C(13);
N=13    rate = 10.64 seconds per node
NULL


The time of TNode::Clone() + TNode::GetListOfNodes()->Add() depends strongly
from nodes amount.
Why? 

Thanks,
Alexander Zvyagin.

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