Jacek,
Thank you for reporting these problems.
I analyzed the problem. Both are CINT syntax limitation.
Please use simple expression.
I'll think if those can be fixed, however, I can not put priority on fixing
this kind of complex expression which you can easily find simpler and
clearer ones. CINT is not aimed to be 100% C/C++ compliant interpreter.
NOT RECOMMENDED SIMPLE EXPRESSION RECOMMENDED
return a=b; vs a=b; return a;
f()[1] = val; vs int* tmp=f(); tmp[1]=val;
Best Regard,
Masaharu Goto
1) returning reference of assignment expression.
In following class XYZ, member function x and z returns reference.
class XYZ {
public:
int p_x;
int p_y;
int p_z;
int &x(int xx) {cout << "xx -> " << xx << " p_x -> " << p_x << endl;
return p_x=xx;}
int y(int &yy) {cout << "yy -> " << yy << " p_y -> " << p_y << endl;
return p_y=yy;}
int &z(int &zz) {cout << "zz -> " << zz << " p_z -> " << p_z << endl;
return p_z=zz;}
};
The problem is in 'return p_x=xx;'. CINT returns reference to xx. This
causes the problem. Please separate assignment and return statement.
p_x=x;
return p_x;
2) In following source, XYZ::x , y, z returns pointer. In main function,
[] operator is used for the return value of the function.
f()[0] = value;
Unfortunately this kind of syntax is not supported in CINT. Please rewrite
this as
int *tmp = f();
tmp[0] = value;
-------------------------- trial2.cxx BEGIN --------------------------
#include <stream.h>
class XYZ {
public:
int p_x[10];
int p_y[20];
int p_z[30];
int *x() {return p_x;}
// int *y() {return p_y;}
int *y() {cout << "*p_y -> " << *p_y ;*p_y=6;cout << " -> " << *p_y <<
endl;return p_y;}
int *z() {return p_z;}
XYZ() {return;}
~XYZ() {return;}
int *x(int xx) {cout << "xx -> " << xx << " *p_x -> " << *p_x <<
endl;p_x[0]=xx;return p_x;}
int *y(int yy) {cout << "yy -> " << yy << " *p_y -> " << *p_y <<
endl;p_y[0]=yy;return p_y;}
int *z(int zz) {cout << "zz -> " << zz << " *p_z -> " << *p_z <<
endl;p_z[0]=zz;return p_z;}
};
main()
{
XYZ *xyz = new XYZ;
cout << "donald duck" << endl;
xyz->x(1)[0] = 10; cout << "xyz->x(1)[0] = 10 -> " << *xyz->p_x << endl;
xyz->y(2); cout << "*xyz->y(2) -> " << *xyz->p_y << endl;
xyz->z(3)[0] = 30; cout << "xyz->z(3)[0] = 30 -> " << *xyz->p_z << endl;
xyz->x()[0] = 4;
xyz->y()[0] = 5; cout << "*xyz->y() = 5 -> " << *xyz->p_y << endl;
cout << *xyz->x() << " " << *xyz->y() << " " << *xyz->z() << endl;
cout << "miki mouse" << endl;
}
This archive was generated by hypermail 2b29 : Tue Jan 04 2000 - 00:43:31 MET