Re: [ROOT] Stand Alone Root Tree.

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Hi Patrick,

I don't know what you mean by a "stand alone Tree"

Below is an example of a simple main program creating a Tree with
the corresponding compile/link instruction showing the minimum number
of libs to link with (Linux):

g++ -o ts ts.cxx -I$ROOTSYS/include -L$ROOTSYS/lib -lCore -lCint -lTree -ldl

//file ts.cxx
#include "TTree.h"
#include "TFile.h"
   
int main() {
   TFile f("simple.root","recreate");
   double a; int i;
   TTree *T = new TTree("T","test");
   T->Branch("a",&a,"a/D");
   T->Branch("i",&i,"i/i");
   for (i=0;i<1000;i++) {
      a = i+0.001;
      T->Fill();
   }
   T->Write();
}


Rene Brun

Patrick Murray wrote:
> 
> I hope this is not a dumb question:)
> 
> I want to use a "stand alone" root tree in the CMS EMU Daq. So the
> question: Is there some subset of root classes that will allow me to do
> this or will I need a full istallation of root on each of my Nodes??
> 
> Thanks,
> Pat

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